3.6+7.2k <25.2 what the answer

1 answer:

8 0

Here are the steps to solving:
1) Write out problem 3.6+7.2k <25.2
2) Subtract 3.6 7.2k <21.6
3) Divide by 7.2 k <3

So k<3 would be your answer

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for two positive integers a and b, we know g c d (a comma b )equals 15 comma space l c m (a comma b )equals 90, what is a b?

Scilla [17]

Two positive integers have gcd (a, b) = 15 and lcm (a, b) = 90. Those two numbers are 15 and 90 or 30 and 45.

Suppose we have 2 positive integers, a and b, then:

gcd (a, b) = the greatest common divisor = common prime factors of a and b

lcm (a, b) = the least common multiple = multiplication of the greatest common prime factors of a and b

In the given problem:

gcd (a, b) = 15

prime factorization of 15:

15 = 3 x 5

Hence,

a = 3 x 5 x ....

b = 3 x 5 x ....

lcm (a, b) = 90

prime factorization of 90:

90 = 3 x 5 x 2 x 3

Therefore the possible pairs of a and b are:

Combination 1:

a = 3 x 5 = 15

b = 3 x 5 x 2 x 3 = 90

Combination 2:

a = 3 x 5 x 2 = 30

b = 3 x 5 x 3 = 35

We can conclude the two integers are 15 and 90 or 30 and 45.

Learn more about gcd here:

brainly.com/question/16969353

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1 year ago

Prove this identity sin^2θcsc^2θ=sin^2θ+cos^2θ by simplifying both sides of the equation.

Gwar [14]

$\bf \begin{array}{rllll} sin^2(\theta )csc^2(\theta )&=&sin^2(\theta )+cos^2(\theta )\\\\ ~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \cdot \cfrac{1^2}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }&=&1\\\\ 1^2&=&1\\ 1&=&1 \end{array}$