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Alinara [238K]
2 years ago
13

Solve 4,500 ÷ 9 = ___ using mental math.

Mathematics
2 answers:
Pachacha [2.7K]2 years ago
7 0

Answer:

<em>4,500 ÷ 9 = 500</em>

<em>hope this helps</em><em> </em><em><</em><em>3</em>

soldi70 [24.7K]2 years ago
6 0

Answer:

500

Step-by-step explanation:

1. 500

2. 1,000

3. 1,500

4. 2,000

5. 2,500

6. 3,000

7. 3,500

8. 4,000

9. 4,500

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Brionna bought a house for $300,000 in 2000. Unfortunately, the market is not doing so hot and each year she loses $2,000 in val
dlinn [17]

Answer:

the answer to the problem is m=-2000

5 0
2 years ago
3.<br> Simplify 32 • 35. (4 points)<br><br><br> 37<br><br> 310<br><br> 97<br><br> 910
Anarel [89]
Hey there!

In order for you to solve for this equation, you need to multiply. That’s what the “•” is or means!

32 • 35 = ?

None of the above, because 32 times 35 equals 1,120

Answers 1,120 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)
7 0
2 years ago
Read 2 more answers
A researcher wishes to estimate the average blood alcohol concentration​ (BAC) for drivers involved in fatal accidents who are f
Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 ​g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~   t_n_-_1

where, \bar X = sample mean BAC = 0.16 g/dL

            s = sample standard deviation = 0.080 ​g/dL

            n = sample of drivers = 60

            \mu = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, \mu is;

P(-1.672 < t_5_9 < 1.672) = 0.90  {As the critical value of t at 59 degrees of

                                              freedom are -1.672 & 1.672 with P = 5%}    P(-1.672 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.672) = 0.90

P( -1.672 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.672 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.672 \times {\frac{s}{\sqrt{n} } } , \bar X+1.672 \times {\frac{s}{\sqrt{n} } } ]

                                       = [ 0.16-1.672 \times {\frac{0.08}{\sqrt{60} } } , 0.16+1.672 \times {\frac{0.08}{\sqrt{60} } } ]

                                       = [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0
3 years ago
If 1/2 of a loaf of brown bread costs R6,how much will 2 halves cost​
dimulka [17.4K]

Step-by-step explanation:

1/2 is equal to R6.

So 2 halves mean R6+R6=R12

Or

R6×2= R12

Answer:R12

5 0
2 years ago
2/9 of the students in a school are in 6th grade.
Cerrena [4.2K]

Answer:

depended is the 6th grade

independed the 2/9 students

-by-step explanation:

4 0
2 years ago
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