Help please!!!! thank you in advance. asap too
1 answer:
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Answer:
see below
Step-by-step explanation:
The function is written in vertex form. It has a negative vertical scale factor, so you know ...
- the vertex is (2, -4)
- the vertical scale factor is 1/2
- the parabola opens downward
Vertex form is ...
f(x) = a(x -h)^2 +k . . . . . . . . . . vertical scale factor "a", vertex (h, k)
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Since you know the vertex and scale factor, you can plot some points on the graph. I find it convenient to think in terms of units either side of the vertex. These are values of x that would make (x-2)^2 be 1^2, 2^2, 3^2, 4^2 and so on. The vertical scale factor of -1/2 tells you that the y-differences for these points will be -1/2, -4/2, -9/2, -16/2 from the vertex. Then we have ...
vertex: (2, -4)
1 unit either side of the vertex: (1, -4.5), (3, -4.5)
2 units either side of the vertex: (0, -6), (4, -6)
3 units either side of the vertex: (-1, -8.5), (5, -8.5)
4 units either side of the vertex: (-2, -12), (6, -12)
You can plot these points and draw a smooth curve through them. Or, you can let a graphing calculator do it. The result will be similar to that shown below.
Answer:
Increasing on the interval(s)
Decreasing on the interval(s)
Step-by-step explanation:
Anytime the graph is going upward, the function is increasing. However, anytime the graph goes down, the function is decreasing. Look at the image below for further reference. Also, when the function is increasing, the slope is positive, and when the function is decreasing the slope is negative.
The increasing interval of the graph is -3
The decreasing interval of the graph is 0.5
Since the values are in the middle of the interval, it automatically becomes the answer.
