Answer:
We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.
Step-by-step explanation:
For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive
The confidence level is given 95%, the significance level would be given by
and
. And the critical values are:
The estimated proportion of people satisfied with the quality of education the students receive is given by:

The confidence interval for the proportion if interest is given by the following formula:
And replacing the info given we got:
We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.
Answer:
n= 1/2 (
) or (0.5)
AND
n= -3/2 (
) or (-1.5)
Step-by-step explanation:
4n^2+4n=3
step1: move 3 to the other side and make the equation equal to zero.
4n^2+4n-3=0
step2: factorise the equation.
(2n-1)(2n+3)=0
step3: make each bracket equal to zero.
2n-1=0
2n+3=0
step4: solve for n values.
<u>1.</u> 2n-1=0
(add 1 for both sides)
2n=1
(divide by 2 for both sides)
n= 1/2 (
) or (0.5)
<u>2.</u> 2n+3=0
( subtract 3 for both sides)
2n=-3
(divide by 2 for both sides)
n= -3/2 (
) or (-1.5)
Answer:
<u>Alternative hypothesis 1</u>: the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2</u>: the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
Recall that the null hypothesis is the fact you want to refute and is in doubt.
So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes.
</em>
The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:
<u>Alternative hypothesis 1:</u> the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2:</u> the mean amperage at which the fuses burn out is < 40 amperes.
sorry to my answer ineed a point and i ask a question sory and thnks:(