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jek_recluse [69]
2 years ago
12

A 10-acre field produced 750 bushels of corn. At that rate,how corn can be produced from a 14-acre field?( explain in steps) Ple

ase Help me Right Answer.
Mathematics
2 answers:
Otrada [13]2 years ago
5 0
750 bushels = 10 acre 
750 bushels/10 acre = 75 bushels per 1 acre
so if 75 bushels = 1 acre you must multiply that by 14
14 x 1 = 14 and 75 x 14 = 1,050
So the answer is that you can produce 1,050 bushels of corn from a 14 acre field. 
Sorry if this makes no sense. 

shtirl [24]2 years ago
5 0
14-acre field* (750 bushels/ 10-acre field)= 1,050 bushels.
(Note that the unit cancels out)

The final answer is 1,050 bushels~
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3 years ago
Simplify 7 - (-4) + 3(-6)
jeka94

Answer:

-7

Step-by-step explanation:

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3 years ago
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What is an equation of the line that passes through the point (−8,−1) and is parallel to the line x-4y=4x
avanturin [10]

Answer:

y = -3/4x - 7

Step-by-step explanation:

Parallel lines have the same slope.

Solve for y in the equation to find the slope.

x - 4y = 4x

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  -4y = 3x

     y = 3/-4 x   = -3/4x    So the slope is -3/4  which is the coefficient of the

                                       x term

Substitute the slope(m) = -3/4 and point (-8, -1) into y = mx + b to solve for "b"

y = mx + b

-1 = -3/4(-8) + b

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-1 - 6 = b

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The equation of the new line:  y = mx + b

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5 0
2 years ago
The number of square feet per house is normally distributed with a population standard deviation of 154 square feet and an unkno
11111nata11111 [884]

Answer: (1500.66,1599.34)

Step-by-step explanation:

Confidence interval for population mean:

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

,where \overline{x} = Sample mean , n= Sample size, z* = critical two tailed z-value , \sigma = population standard deviation.

As per given , we have

n= 16

\sigma = 154 square feet

\overline{x}= 1550 square feet

\alpha= 1-0.80 = 0.20

Critical z-value = z_{\alpha/2}=z_{0.2/2}=z_{0.1}=1.2815

Confidence interval for population mean:

1550\pm (1.2815)\dfrac{154}{\sqrt{16}}\\\\ = 1550\pm (1.2815)\dfrac{154}{4}\\\\= 1550\pm 49.33775\\\\ =(1550-49.33775,\ 1550+49.33775)\\\\\approx (1500.66,\ 1599.34)

Required confidence interval:  (1500.66,1599.34)

6 0
2 years ago
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