Answer:
see below
Step-by-step explanation:
10^33/2
Rewriting the numerator as 10 * 10 ^ 32
10 * 10 ^32
--------------------
2
10/2 = 5
5 * 10 ^32
Therefore
10^33/2=5*10^32
X=1/2
Hope this helped! :3
Answer:

Not a function.
Step-by-step explanation:
The given function is;

Let 
Interchange x and y;

Solve for y;

Square both sides




The inverse is

is not a function because one x-value maps onto to different y-values.
Urface area = area of the square + area of the 4 triangles
= 6*6 + 4(1/2*6*6)
= 36 + 4 * 18 = 108 sq cms