Let the unknown number be x.
5/11 * x = 55
Since x is being multiplied by 5/11, and you want x alone, you need to multiply both sides of the equation by the reciprocal of 5/11 which 11/5.
11/5 * 5/11 * x = 55/1 * 11/5
x = 605/5
x = 121
Answer: The number is 121.
Answer:
75 degrees
Step-by-step explanation:
Complementary angles equal 90 degrees together. That is the case with angle X and Y. Set an equation to describe the situation.
Y=1/5X
X=5Y
Now, set another equation:
X+Y=90
Substitute the first equation into the second one.
5Y+Y=90
6Y=90
Y=15
Substitute this once again:
X+15=90
X=75
Please find the attachment.
Let x represent the side length of the squares.
We have been given that an open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the sides. We are asked to find the volume of the box.
The side of box will be
and
.
The height of the box will be
.
The volume of box will be area of base times height.
![\text{Volume of box}=(8-2x)(10-2x)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%288-2x%29%2810-2x%29%5Ccdot%20x)
Now we will use FOIL to simplify our expression.
![\text{Volume of box}=(80-16x-20x+4x^2)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%2880-16x-20x%2B4x%5E2%29%5Ccdot%20x)
![\text{Volume of box}=(80-36x+4x^2)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%2880-36x%2B4x%5E2%29%5Ccdot%20x)
Now we will distribute x.
![\text{Volume of box}=80x-36x^2+4x^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D80x-36x%5E2%2B4x%5E3)
![V(x)=80x-36x^2+4x^3](https://tex.z-dn.net/?f=V%28x%29%3D80x-36x%5E2%2B4x%5E3)
Therefore, the volume of the box would be
.
The base of a cone is something circular, like a circle or an ellipse.
The rest of the options (square, triangle, and pentagon) are all based of pyramids, not cones. Cones have to have a circular base because otherwise they'd be pyramids.