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Neko [114]
3 years ago
6

The drama club sold 415 Manatee tickets to the school's play for $7.95 each 18 of the tickets were refunded estimate the tickets

is your estimate and overestimate or an underestimate. PLZ HELP ASAP!!!!!!
Mathematics
1 answer:
nevsk [136]3 years ago
6 0
Since you always round up when you estimate in the middle lets say theres 420 tickets. Each is 7.95, but we'll round it to 8.00. 420x8.=3,360. After that part we need to find about how much tickets were refunded. So we round 18 to 20 and each ticket is still 8$. 20x8=160. Finally in all, we do 3,360-160=3200. Its an overestimate because we rounded up. Im not sure what else youre asking but thats the basic answer.
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Step-by-step explanation:

One way to solve the quadratic equation x2 = 9 is to subtract 9 from both sides to get one side equal to 0: x2 – 9 = 0. The expression on the left can be factored: (x + 3)(x – 3) = 0. Using the zero factor property, you know this means x + 3 = 0 or x – 3 = 0, so x = −3 or 3.

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Write as a single power, then<br> evaluate.<br> (3^3)^4
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<h3>531,441</h3>

Step-by-step explanation:

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3 years ago
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How many points will I get if I get 60 points every 5 mins and it goes on for 4 hours?
stiks02 [169]

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well u multiply 60 and 12 which is 720 then multiply that by 4 that equals 2,880 more points

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3 years ago
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Jobisdone [24]
A/2.8 • 2.8
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Answer:
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Hope this helps!
7 0
3 years ago
When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

5 0
3 years ago
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