All direct proportional graphs go through the origin (0,0). So this is where one point could go. The second point is found by going up 5 units and then to the right 3 units to get to (3,5)
<h3>Draw a straight line through (0,0) and (3,5) to graph</h3>
The equation of this line is y = (5/3)x
Looking for the area of a regular figure would be taking the longest side and the shortest side and multiply
Answer:
C
Step-by-step explanation:
cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13
Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
Answer:
2.4
Step-by-step explanation:
24/10=2.4