1,995 for each game.
1,995+1,995=3,990
3,990+295=4,285.00
Answer:
40 ft
Step-by-step explanation:
The fiagram shows the right triangle (one angle is right angle).
By the Pythagorean theorem,
From the diagram,
then
Answer:
16.3°
Step-by-step explanation:
Cos x = adjacent side/hypotenuse
= 24/25
x = arccos (24/25) = 16.3°
You must memorize the definitions of the trig functions and then this type of problem is easy. OK?
Answer:
<em>We are given that,</em>
<em>Polygons ABC and DBC are triangles.</em>
<em>Also, ABC and DBC are </em><em>Right</em><em> Triangles as ∠ABC and ∠DBC are 90 respectively.</em>
<em>AB ↔ CD</em>
<em>Now,</em>
<em>From the </em><em>HL Congruency </em><em>we know that,</em>
<u><em>"Two </em></u><u><em>Right</em></u><u><em> triangles are congruent if the </em></u><u><em>Hypotenuses </em></u><u><em>and at least </em></u><u><em>One Side </em></u><u><em> of both the triangles correspond to each other.</em></u><em>"</em>
<em>Here,</em>
- <em>Triangles ABC and DBC were given to be right triangles.</em>
- <em>AB </em><em>and </em><em>CD</em><em> are the hypotenuses of </em><em>ΔABC</em><em> and </em><em>Δ DBC</em><em> respectively. (From the construction of the figure) and are given equal.</em>
- The Side BC of both the triangles correspond as they share the side BC together.
Here, As the three conditions of being congruent through HL Congruency are satisfied, ΔABC & Δ DBC are congruent through the HL Congruency Criterion.
<em>ΔABC</em><em> ≅ </em><em>Δ DBC </em><em>[Hence, Proved]</em>
