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mel-nik [20]
2 years ago
9

Given an = a + (n − 1)(d)

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

345hope this helps

Step-by-step explanation:

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QUESTION 5 of 10: You are considering selling your home. You consult with an agent who gives you the asking prices of five homes
san4es73 [151]

Answer: $169,500

Step-by-step explanation:

The mean simply means the average price of a set of a numbers that are given. For one t calculate the mean, one has to add the numbers that are given and then divide them by the amount of numbers.

I'm the case above, the numbers given are $165,000, $188,000, $175,000, and $150,000.

Mean = ($165,000 ,+ $188,000 +$175,000 + $150,000) ÷ 4

= $678,000/4

= $169,500

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3 years ago
What is 3 ÷ 1/2 can you help me with this
Vsevolod [243]

Answer: 1.5 or 1 1/2

Step-by-step explanation:

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3 years ago
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I really need help with this 6th grade work due today
DIA [1.3K]

5

Step-by-step explanation:

Length (L) = u

Breadth (b) = 6 mi

Perimeter (P) = 22 miles

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P = 2 (L+ b)

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11 = u + 6

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3 years ago
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Find the H.C.F of the following expressions.{x²-3x,x²-9}​
lora16 [44]

Answer:

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

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A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
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