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Alchen [17]
3 years ago
7

Are these shapes congruent?

Mathematics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

there are congruent

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In how many distinct ways can the letters of the word mathematics be arranged? (first, does the order matter?)
TEA [102]
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).

Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
4 0
3 years ago
32/8+2*12 what is the answer?
lidiya [134]

Answer:

The correct answer is 28

Step-by-step explanation:

7 0
3 years ago
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Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
Solve the equation. Write your answer as an integer or simplified fraction.
saw5 [17]

<u>Corrected question :</u>

Solve the equation. Write your answer as an integer or simplified fraction.

  • 8n - 7 (n - 2) = 18

<u>Required Solution :</u>

The given equation,

  • 8n - 7 (n - 2) = 18

★ Multiplying -7 into (n - 2),

>> 8n - 7 × (n - 2) = 18

>> 8n - 7n + 14 = 18

★ On substracting 7n from 8n we gets,

>> n + 14 = 18

★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),

>> n = 18 - 14

>> n = 14

★ Therefore,

  • Value of n is 14.

<u>Learn</u><u> more</u><u> from</u><u> brainly</u><u>.</u><u>c</u><u>o</u><u>m</u><u> </u><u>:</u>

brainly.com/question/27432186

brainly.com/question/22661149

brainly.com/question/26727230

6 0
2 years ago
Write the decimal expansion for seven ninths
AysviL [449]

Answer:

On my calculator it appears as 0.7 recurring

6 0
3 years ago
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