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NikAS [45]
2 years ago
14

The sum of two numbers is -47 and their difference is one. Find the numbers. Separate with a comma.

Mathematics
1 answer:
Rudik [331]2 years ago
7 0

Answer:

-23, -24

Step-by-step explanation:

Adding negative numbers gets you another negative number. Therefore the numbers must be -23 and -24.

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8. Consider the diagram below. Solve for k.
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Mr. Smith wants to order some pizza and cheese pizza cost $11 and pepperoni pizza cost $12.50 if you bought 13 pieces total and
Triss [41]

Answer: Mr Smith bought 7 pepperoni pizza

Step-by-step explanation:

Step 1

cost of cheese pizza  =$11

pepperoni pizza cost =$12.50

let number cheese pizza be represented as c

and number of pepperoni pizza be represented as p

such that the total number of pizza  bought which equals 13 can be represented as

c+ p= 13

and total cost of both pizza  can be expressed as

11c+ 12.50p =153.50

Step 2 Solving

 c+ p= 13

11c+ 12.50p =153.50

By elimination method, Multiply equation 1 by 11 and subtract the new equation from equation 2

11c+ 12.50p =153.50

11c+ 11p=143.

1.5p =10.5

p= 10.5/ 1.5 =7

c+ p= 13

c= 13-p =13-7=6

Therefore Mr Smith bought 6 cheese pizza and 7 pepperoni pizza

6 0
2 years ago
Jupiter has a diameter $86,881 mi. What is the circumference of the planet?<br> C=___in<br> C=___mi
Sophie [7]

Answer:

10) 87.96 in

15) 272,944.7 in

7 0
10 months ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Eduardwww [97]

Answer:

(A)  H_0 : μ = 22 ; H_A : μ ≠ 22

(B) Value of the test statistic = -2.69

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

We have to test the accuracy of the bottling process.

(A) Let, NULL HYPOTHESIS, H_0 : \mu = 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

ALTERNATE HYPOTHESIS, H_A : \mu \neq 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that will be used here is One-sample z-test;

             T.S. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounces

            n = sample of bottles = 65

(B) So, <u>test statistics</u> =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }

                                  = -2.69

Hence, the value of test statistics is -2.69.

6 0
3 years ago
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