PLEASE HELP EXTRA POINTS / WRONG ANSWERS WILL BE REPORTED
1 answer:
Q1. The limit from the right is -4. (The limit from the left, and the value of f(3) are different, but that doesn't matter for the question asked. Taken together, they mean that the limit as x approaches 3 does not exist. But that is not the question asked.)
Q2. f(x) = 4/x.
f'(x) = -4/x^2, so f'(2) = -4/2^2 = -1.
Q3. Since the denominator is zero at x=7, the only answer choice that makes any sense is the first one:
-∞; x = 7
It also happens to be the right one.
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Answer:
The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )
Step-by-step explanation:
Given equation as :
3 x² + 6 x +15 = 0
The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as
x =
So , from given eq , the value of x is now obtain as
x =
Or, x =
Or, x =
∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )
Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer