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34kurt
3 years ago
14

PLEASE HELP EXTRA POINTS / WRONG ANSWERS WILL BE REPORTED

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Q1. The limit from the right is -4. (The limit from the left, and the value of f(3) are different, but that doesn't matter for the question asked. Taken together, they mean that the limit as x approaches 3 does not exist. But that is not the question asked.)


Q2. f(x) = 4/x.

f'(x) = -4/x^2, so f'(2) = -4/2^2 = -1.


Q3. Since the denominator is zero at x=7, the only answer choice that makes any sense is the first one:

-∞; x = 7

It also happens to be the right one.

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1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

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Answer: option B.
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