Answer:
42cm²
Step-by-step explanation:
because if the perimeter of the rectangle is 28 then the length is 5, 5 - 11 = 6, the formula for finding the trapezium is to add the 2 parallel sides, half them, then times them with the length so your sum will look like this, 5+9=14, (i knew the other side was 9 as the length of AB is the same as the length of FC, which is the one of the parallel sides of the trapezium) then we do 14÷2=7, finally we times 7 by 6 which is 42cm²
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
Given:
y varies directly with x
y = 8 when x = -6
what is the value of y when x = -2?
y = kx
we need to get the constant of variation.
8 = k(-6)
8/-6 = k
4/-3 = k or - 1 1/3
y = -4/3 (-2)
y = (-4*-2) / 3
y = 8 / 3
y = 2 2/3 OR 2.67
The correct answer is Choice B. y = -1.33x ; 2.67
Answer:
Option C
Step-by-step explanation:
Point diagrams show the frequency of occurrence of a series of events after a certain number of trials. In this case, the trials were 100. During each trial it would have been possible to have proportions of {0.24, 0.25, 0.26, 0.27, 0.28 ..... 0.56}
The events with the highest probability of occurrence are those with the highest number of points in the diagram.
Note that the distribution of the points resembles a bell, with a peak (greater clustering of points) between 0.35 and 0.41.
This indicates that it is more likely that the proportion of employees who go to work in bicycles will be between 0.35 and 0.41.
Then the diagram seems to indicate that a proportion less than 0.30 or greater than 0.45 is unlikely (they have less number of points)
Based on this analysis, it can be concluded that the correct option is c)
c) It is plausible that 40% of the population rides a bike to work because the data shows that a sample proportion of 29% is unlikely.
