Answer:
Step-by-step explanation:
The answer depends on whether the interest is simple or compound.
For simple interest:
A = 670(1 + 0.08)(24)
For compound interest
A = 670(1 + 0.08)24
The polynomial has two terms. The exponent of the first term is two. The exponent of the second term would be 1 because 5xy^1 is equal to 5xy.
6= 4(z+9)/y+2
6y +12 =4(z+9)
6y=4(z+9) -12
y=(4(z+9)-12)/6
y=2z+18-6/3
y=2z+12 /3
Alright...simple...showing all steps.. ;)
You have the equations...
2x+y=7
and
3x+5y=14
To be able to even solve for any of the variables...multiply the equations by...2...and..3...
2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28
Thus,
6x+3y=21
-
6x+10y=28
=========
-7y=-7
y=1
Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....
2x+(1)=7
2x+1=7
-1 -1
2x=6
x=3
Thus, the point of intersection for these two equations is (3,1)
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
