9514 1404 393
Answer:
a = 6, b = 12, c = 6, d = 6√3
Step-by-step explanation:
The two triangles are the "special" triangles.
The 45-45-90 triangle has side lengths in the ratios 1 : 1 : √2.
The 30-60-90 triangle has side lengths in the ratios 1 : √3 : 2.
Then ...
c : a : 6√2 = 1 : 1 : √2 ⇒ c = a = 6
and ...
a : d : b = 1 : √3 : 2 ⇒ d = 6√3 and b = 12 . . . (since a=6)
The lengths are ...
a = 6, b = 12, c = 6, d = 6√3
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
Answer: if you are going to put it like p^2-m^2 no one going to have that answer so I need the p and the m like for example the p=5 and the m=4
Step-by-step explanation: so it going to be like
Evaluate for m=4,p=5
5^2−4^2
=9
So I can’t answer how you put it
Use pythagorean theory
a^2 + b^2 = c^2
5^2 + 12^2 = 169
square root of 169 is 13
the missing side length is 13 in
