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2 years ago

Someone help its due

Mathematics

2 answers:

Sphinxa [80]2 years ago

7 0

Answer:

Step-by-step explanation:

PQR = 150.

RPQ = PRQ

RPQ + PRQ = 30

RPQ = 15

Fudgin [204]2 years ago

4 0

15 is the answer, if it’s wrong im not sure what else it’d be

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What is the Gcf of 10,20,78

Ksivusya [100]

The answer to this is 2. Ten only has two factors, 5 and 2, and 2 can be decided evenly amongst them all.

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3 years ago

The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown.

omeli [17]

Answer:

The area of one trapezoidal face of the figure is 2 square inches

Step-by-step explanation:

The complete question is

The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?

we know that

The area of a trapezoid is given by the formula

$A=\frac{1}{2}(b_1+b_2)h$

where

b_1 and b-2 are the parallel sides

h is the height of the trapezoid (perpendicular distance between the parallel sides)

we have

$h=1\ in\\b_1=1\ in\\b_2=3\ in$

substitute the given values in the formula

$A=\frac{1}{2}(1+3)(1)$

$A=2\ in^2$

8 0

3 years ago

Read 2 more answers

Explain how to construct a perpendicular bisector. ?

inysia [295]

Open the compass it is more than half of the distance between a and b, and scribes arcs of the same radius centered at a and b. call the two points where these two arcs meet c and d. Draw the line between c and d. CD it is the perpendicular bisector of the line segment AB. call the point where CD intersects AB and E

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2 years ago

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I need help on 17 and 23 pls

ludmilkaskok [199]

Question # 17 Solution

Answer:

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Step-by-step Explanation:

The given expression

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

And we have to solve for x₁

So,

Lets solve for x₁.

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Multiply both sides by x₂ - x₁

$m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m(x_{2}-x_{1})= (y_{2}-y_{1})$

$mx_{2}-mx_{1}= (y_{2}-y_{1})$

$-mx_{1}= y_{2}-y_{1}-mx_{2}$

Divide both sides by -m

$\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}$

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Therefore, $x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Question # 23 Solution

Answer:

$n= \frac{bx}{-b + x}$

Step-by-step Explanation:

The given expression

$\frac{nx}{b}-x=x$

And we have to solve for n

So,

Let's solve for n.

$\frac{nx}{b}-x=x$

Multiply both sides by b.

$-bn + nx = bx$

Factor out n.

$n(-b + x)= bx$

Divide both sides by -b + x.

$\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}$

$n= \frac{bx}{-b + x}$

Therefore, $n= \frac{bx}{-b + x}$

Keywords: solution, equation

Learn more about the solution of equations from brainly.com/question/12864981

#learnwithBrainly

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3 years ago

Complete the following statement: f(3)=_____

Lesechka [4]

Using this equation, f(3) = 23.

In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.

f(x) = 2x^2 + 5sqrt(x - 2)

Now place 3 in for each x.

f(3) = 2(3)^2 + 5sqrt(3 - 2)

Now square the 3.

f(3) = 2(9) + 5 sqrt(3 - 2)

Do the subtraction inside of the parenthesis.

f(3) = 2(9) + 5sqrt(1)

Take the square root

f(3) = 2(9) + 5(1)

Multiply.

f(3) = 18 + 5

And add.

f(3) = 23

4 0

3 years ago