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3 years ago

Explain how to draw a line segment that measures 72 millimeters.

Mathematics

1 answer:

andrew-mc [135]3 years ago

7 0

Answer:

You can use a ruler

Step-by-step explanation:

brainliest?

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Solve for n. 2/3(1 + n) = - 1/2n

alexandr1967 [171]

Answer:

⅔+⅔n=-½

6×⅔+6×⅔n=6×-½

2×2+2×2n=-3

4+4n=-3

4n=-3-4

4n=-7

n=-7/4

8 0

3 years ago

(UPE) Terremotos são eventos naturais que não têm relação com eventos climáticos extremos, mas podem ter consequências ambientai

Alex

Answer:

E= $10^{18}$ Joules

Step-by-step explanation:

1) Olá! Adicionando dados faltantes ao enunciado, como a fórmula dada: $M=\frac{2}{3}log(\frac{E}{E_{0}})\\$ e corrigindo a quantidade de Energia inicial: $10^{4,5}$ Vamos seguir aplicando a fórmula, lembrando das propriedades de logaritmo.

$M=\frac{2}{3}log(\frac{E}{E_{0}})\\9=\frac{2}{3}log(\frac{E}{10^{4,5}})*3\\27=2log(\frac{E}{10^{4.5}})\\log(\frac{E}{10^{4.5}})^{2}=27\\(\frac{E^{2}}{10^{9}})=10^{27}\\E^{2}=10^{27}*10^{9}\Rightarrow E=\sqrt{10^{36}}\rightarrow E=10^{18} Joules$

6 0

3 years ago

I just wanna make sure my answer is right can anyone confirmmm

valina [46]

You would get it wrong cause you haven’t answered anything

3 0

2 years ago

The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find

dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean $(\mu)$ of 2500 hours and standard deviation $(\sigma)$ of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: $Z=\dfrac{X-\mu}{\sigma}$

For X = 2470

$Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5$

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0

2 years ago

As – 16a,<br> as – 4a3,<br> 2a3 + 8a - 4a2 - 16

vfiekz [6]

Answer:

1) as-16a

taknig a as common

=a(s-16)

2)as-4a³

taking a as common

=a(s-4a²)

3)2a³+8a-4a²-16

taking common terms

=2a(a²+4)-4(a²+4)

=(2a-4)(a²+4)

again taking common

=2(a-2)(a²+4)

i hope this will help you :)

7 0

3 years ago