The distance between the boats after 1 minute would be 130 ft.
Given that a lake is 200ft wide, and two boats start to move towards one another from opposite shores, and in one minute, the first boat goes 40 ft and the second one goes 30 ft, to determine what would be the distance between the boats after 1 minute the following calculation must be performed:
- Total width - boat distance 1 - boat distance 2 = Distance after 1 minute
- 200 - 40 - 30 = X
- 130 = X
Therefore, the distance between the boats after 1 minute would be 130 ft.
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The answer is attachment 3 Because the y intercept is -5 and it goes down three and to the left 4.
Well, what is 6% of "v"? well, 6% of anything is just 6/100 * anything, so 6% of v is just 6/100 * v or 0.06v
so, v + 0.06v is just 1.06v <--- that'd be the increased price for <1900, 950>
well, what's that vectors wise? < 1900 * 1.06 , 950 * 1.06 >
that is <2014 , 1007>
now.. the Revenue is just price * quantity
so, I take it, it's just asking for the dot product of <2014, 1007> • <2700, 3700>
which should just be (2014 * 2700) + (1007 * 3700)
(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y

= y
Answer for (a):
=
(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y:
Answer for (b):
= 
(c)

replace all t's in the

equation with

=

=

=

=
Answer for (c):
= 
(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1
(e)
h(g(t)) = 8t - 1
y = 8 t - 1
t = 8y - 1
t + 1 = 8y

= y
Answer for (e): inverse of h(g(t)) =
0.0035 is the answer brainliest plz