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Andrej [43]
3 years ago
11

Please help me how to graph y = 44 + 3x

Mathematics
1 answer:
astraxan [27]3 years ago
7 0
Okay, so this is actually relatively simple:
Go up 44 units on the y-axis, where x=0, and put a point. Now, since the slope is 3x, you move 3 units up, and 1 unit right, and place a point. Do this about 3 times, continuing to make points up 3, over 1. You can also move 3 units down and 1 unit left from the point at (0,44) because by moving down, you move -3 units, and by moving left, you move -1 units. This causes the negatives to cancel out, and you keep the slope of 3. 
I hope this explanation makes sense; good luck!

To solve algebraically:
Plug in any number for x, besides 0 because the y-intercept is (0,44). We will use 1 for our x.
y=44+3x
y=44+3(1)
y=44+3
y=47
And so, (1, 47) would be our point
You can use -1, as well.
y=44+3(-1)
y=44-3
y=41
(-1, 44) would be our point
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3 years ago
Can you help me find the value of X?
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Step-by-step explanation:

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The relationship between z and x is ...

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Write the ratio as a fraction in lowest terms.<br> 15 minutes to 3 hours
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Part A is 5/6 of the whole

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The fractions are then:

15/18 and 3/18

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Part A is 15/18 of the whole

Part B is 3/18 of the whole

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7 0
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Read 2 more answers
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
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