<span>A number is divisible by 9, if the sum is a multiple of 9 or if the sum of its digits is divisible by 9.
</span>
Answer:
56
Step-by-step explanation:
degree of freedom is n - 1, n being the sample size
One sample of 57 participants in a study (given)
For this study, n = 57
Using the degree of freedom formula, 57 - 1 = 56
Hope it helps, Let me know if yoy have any more questions/concerns !
Have a nice rest of your day :)
The answer is 3.42 x 10^6 because we moved the decimal 6 places to the left. Hope this helps:)
~Ash
Answer:
A. x = 2 and y =2
B. x = 3 and y = -1
Step-by-step explanation:
A. {
x = 3y − 4
2x − y = 2
1) Substitute the value of x
2(3y − 4) − y = 2
2) Solve the equation for y
y = 2
3) Substitute the value of y
x= 3(2) -4
4) Solve the equation for x
x = 2
Final Solution: x = 2 and y =2
B. {
3x + 2y = 7
−x + y = −4
1) Multiply both sides of the equation by 3
-3x + 3y = -12
2) Eliminate one variable by adding the equations
3x + 2y = 7
<u>+ (−3x + 3y = −12)</u>
5y = -5
3) Divide both sides of the equation by 5
y = -1
4) Substitute the given value of y into the equation -x + y = -4
-x + (-1) = -4
5) Solve the equation for x
x = 3
Final Solution: x = 3 and y = -1
Answer:
Step-by-step explanation:
The diagram of the triangles are shown in the attached photo.
1) Looking at ∆AOL, to determine AL, we would apply the sine rule
a/SinA = b/SinB = c/SinC
21/Sin25 = AL/Sin 105
21Sin105 = ALSin25
21 × 0.9659 = 0.4226AL
AL = 20.2839/0.4226
AL = 50
Looking at ∆KAL,
AL/Sin55 = KL/Sin100
50/0.8192 = KL/0.9848
50 × 0.9848 = KL × 0.8192
KL = 49.24/0.8192
KL = 60
AK/Sin25 = AL/Sin 55
AKSin55 = ALSin25
AK × 0.8192 = 0.4226 × 50
AK = 21.13/0.8192
AK = 25.8
2) looking at ∆AOC,
Sin 18 = AD/AC = 18/AC
AC = 18/Sin18 = 18/0.3090
AC = 58.25
Sin 85 = AD/AB = 18/AB
AB = 18/Sin85 = 18/0.9962
AB = 18.1
To determine BC, we would apply Sine rule.
BC/Sin77 = 58.25/Sin85
BCSin85 = 58.25Sin77
BC = 58.25Sin77/Sin85
BC = 58.25 × 0.9744/0.9962
BC = 56.98
