How to write 0.326 in two forms

Neporo4naja [7]

First, solve the exponent part because it has a higher precedence than multiplication. And we have a negative exponent. Which means we takes the reciprocal of 4 then take to the power of 4.

4^-4 = 1/4^4 = 1/256

Now do the multiplication part.

16 * 1/256 = 1/16

7 0

3 years ago

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Please help! Thank you! <3

lesantik [10]

I believe the answer is 109 degrees for x.

7 0

3 years ago

What is 14/28 in simplest form?

zhenek [66]

Hi!

The GCM of 14 and 28 is 7. 7 goes into 14 2 times, and goes into 28 4 times. So...

2/4

Which can be simplified further to 1/2

The answer is 1/2

Hope this helps! :)

6 0

3 years ago

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What expression is equivalent to −24x+72?

s2008m [1.1K]

Step-by-step explanation:

the answer is 4. you factor the equation since 24.

7 0

3 years ago

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So:

$Z = \frac{2.75 - 2}{0.283}$

$Z = \frac{0.75}{0.283}$

$Z = 2.65$

$Z = 2.65$ has a pvalue of 0.99598.

This means that the probability that the technican will require at least 2.75 hours to complete one component is 1 - 0.99598 = 0.0042 = 0.42%.

4 0

4 years ago