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MrMuchimi
3 years ago
8

Ismael has a set of 5 solar panels and Ben has a set of 6 smaller solar panels. Each set of panels produce the same amount of en

ergy. 3 of Ismael's panels are on and producing energy. 4 of Ben's are on and producing more energy. Whose solar panels are producing more energy? Explain.
Mathematics
1 answer:
eimsori [14]3 years ago
5 0

9514 1404 393

Answer:

  Ben's

Step-by-step explanation:

If E is the amount of energy that each full set of panels produces, then ...

  3 of Ismael's 5 panels produce 3/5E

  4 of Ben's 6 panels produce 4/6E

We can compare these fractions when they have a common denominator.

  3/5E = 18/30E . . . . energy from Ismael's panels

  4/6E = 20/30E . . .  energy from Ben's panels

  18/30 < 20/30 . . . . so Ben's panels are producing more energy

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Please help me, this is PEDMAS
rusak2 [61]

Answer:

1). 183

2). 83

3). 353

4). -2652

5). 59

6). 510

7). -293

8). 79

9). 78

10). 87

Step-by-step explanation:

Considering order of operation, parenthesis must be simplified first.

The solutions to the given questions are shown below;

1). \ \ 5+(7\times (3+2)^2) + 3=8 +  (7\times (5)^2)  = 8 + (7\times 25) = 8 + 175 = 183

2). \ 16+(8+ (6+2)^2) - 5=16-5 +  (8+ (8)^2)  = 11 + (8+64) = 11 + 72 = 83

3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353

4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4  = (-663)\times 4 = -2652

5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59

6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510

7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 -  324) + 25 = -318 + 25 = -293

8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79

9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78

10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87

3 0
3 years ago
Pls help i will give brainly!!!
Hatshy [7]

Answer:

Greatest population density: Denmark

Smallest population density: The U.S.

Step-by-step explanation:

Population density = population / area

So let's find the population density of each country

For U.S

Population: 272,648,000

Area: 9,364,520 sq km

Population density: 272,648,000/9,364,520=29.1 ( rounded to the nearest tenth )

So the population density of the U.S is 29.1 people per sq km

For Denmark

Population: 5,248,000

Area: 42,077

Population density: 5,248,000/42,077=124.7 ( rounded to the nearest tenth )

So the population density of Denmark is 124.7 people per sq km

For Ghana

Population: 18,339,000

Area: 237,533

Population density: 18,339,000/237,533=77.2 ( rounded to the nearest tenth ).

So the population density of Ghana is 77.2 people per sq km

Now that we have calculated the population density of each country let's look back at the question

Which country has the greatest population density? Which country has the least?

Looking at the population densities we can conclude that Denmark has the largest population density at 124.7 people per sq km and the U.S. has the smallest population density at 29.1 people per sq km

3 0
3 years ago
Read 2 more answers
Completing the square x^2 + 10x
IRISSAK [1]

Answer:

x^2 + 10x + 25

Step-by-step explanation:

(B/2) ^2

10/2 = 5

5^2 = 25

3 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac
Anestetic [448]

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function  is given by the formula

y=a(1+r)^x

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

a=200\\r=8\%=8/100=0.08

substitute

y=200(1+0.08)^x

y=200(1.08)^x

what will Tacoma's population be in 2014?

Find the value of x

x=2014-2000=14\ years

substitute the value of x

y=200(1.08)^{14}=587.439\ thousand

therefore

Tacoma's population in 2014 will be 587,439 people

5 0
3 years ago
Help me on this problems
elena55 [62]
The answer for your problem (1) is 7.41
6 0
3 years ago
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