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Viktor [21]
3 years ago
12

Help! I’ll mark brainliest

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

answer is the second one

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What is the volume of the square pyramid with base edges 4 m and height 3 m?
kicyunya [14]

Answer:

Volume of the pyramid = 16m³ or 16 cubic meters.

Step-by-step explanation:

The equation for the volume of a pyramid is:

V=\frac{b*h}{3}

where b = area of base and h = height.

In this case, the base is a square with a side length of 4m.

Area of the square base = (4m)² = b = 16m²

h = 3m

Insert b and a into the volume of a pyramid equation.

V=\frac{3m*16m}{3}

= 16m³

Volume of the pyramid = 16m³ or 16 cubic meters.

8 0
3 years ago
A gaint kite is contrstrused using bamboo for the edges and diagonals and card for sail. When mapped on the diagram, the ends ar
lisov135 [29]
Rip king Von the only rapper that rapped abt things that mattered
3 0
3 years ago
I need help I will give BRAINLEST
GREYUIT [131]

Answer:

25%

Step-by-step explanation:

To solve this, we can use the percent change formula shown in the picture attached below. x_{2} is the new value, x_{1} is the old value, and C represents the change. For this problem, 80 is the new value and 64 is the old value. Let's plug those numbers into the formula and solve for the percent change:

C = \frac{(80-64)}{64} \\ × 100

C = \frac{16}{64} ×100

C = 0.25 ×100

C = 25%

Thus, the answer is 25%.

7 0
3 years ago
I don’t know how to do this and my teacher doesn’t know how to teacher please help me
AnnyKZ [126]

Answer:

Yeah and i don't know how to answer that sorry

Step-by-step explanation:

you can't look it up some how?

8 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
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