Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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Answer:
In general, when y = f(x), you are substituting a permissible x value into function f & its calculated 'output' is the value for y. Then (x,y) is an ordered pair, i.e. coordinates of a point on the graph. ... So our ordered pair is (-14,11).
Answer:
m = -4
Step-by-step explanation:
First you have to deal with the right side of the equation since it's not spread out.
You therefore have to distribute (in order)
5×1= 5,
5×-m= -5m
And
-2×1 = -2
-2×-m = 2m
Now set it up in the order it was at first (not necessary, but helpful)
15 = 5-5m-2+2m
Add the common values...
5-2= 3
-5m+2m= -3m
Your equation should now look like this:
15= 3-3m
At this point you need to get the common values on the same side, so you would subtract 3 from both sides
15-3= 12
3-3= 0
Since you the 3 cancelled out on the right side, your equation now looks like this:
12= -3m
(Or -3m= 12)
At this point you only need to get m by itself so you would divide by -3 on both sides
-3m/-3= m (or 1m: m is understood as such)
12/-3= -4
The final answer should be
m = -4