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Naddik [55]
3 years ago
6

Match each expression with the equivalent expanded expression.

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

Question

Match each expression with the equivalent expanded expression.

0.5 (2x + 3)

- 10x - 3

1/3 ( 9 +81)

8x - 4

-5 (2x + 3/5)

-2x + 3

2 (4x-2)

x + 1.5

-3 (2/3x - 1)

30

Answer:



Step-by-step explanation:



Step-by-step explanation:

Question

Match each expression with the equivalent expanded expression.

0.5 (2x + 3)

- 10x - 3

1/3 ( 9 +81)

8x - 4

-5 (2x + 3/5)

-2x + 3

2 (4x-2)

x + 1.5

-3 (2/3x - 1)

30

Answer:



Step-by-step explanation:



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36 kg bag of cement was dropped losing one tenth of cement. How much was left in the bag of cement ?
kow [346]

Answer:

32.4kg

Step-by-step explanation:

if it loses one tenth of cement;

36kg×1/10

36kg/10

3.6kg was lost

to find the remaining ; 36kg - 3.6kg = 32.4kg is left in the bag

7 0
3 years ago
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The sum of a number x and 5 equals 14
pav-90 [236]

Answer:

x=9

Step-by-step explanation:

Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.

3 0
4 years ago
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Please help ASAP!!!!!
Viefleur [7K]
Use pythagorean’s theorem
as you can see it’s a right isosceles triangle

so your equation is adapted to this:
p^2 + p^2=44^2
add like terms and simplify
2p^2=1936
divide by 2
p^2=968
square root
p= √968
simplify
p=22√2

the answer would be your second option
3 0
3 years ago
What is 6/10 fraction as decimal
dexar [7]
I am pertty sure its 0.6 but if i am wrong sorry
4 0
3 years ago
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Find the value of x in the triangle shown below​
CaHeK987 [17]

Answer:

<h2>46.4°</h2>

Step-by-step explanation:

Apply sine formula:

\frac{sin \: a}{a}  =  \frac{sin \: b}{b}  =  \frac{sin \: c}{c}

\frac{sin \: a}{a}  =  \frac{sin \: c}{c}

Plug the values

\frac{sin \: (88)}{6.9}  =  \frac{sin \: x}{5}

Apply cross product property

5 \: sin \: (88) = 6.9 \: (sin \: x)

\frac{5 \: sin \: (88)}{6.9}  = sin \: x

x =  {sin}^{ - 1} ( \frac{5 \: sin \:( 88)}{6.9} )

x = 46.4

Hope this helps .....

Best regards!!!

3 0
3 years ago
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