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Naddik [55]
2 years ago
6

Match each expression with the equivalent expanded expression.

Mathematics
1 answer:
adelina 88 [10]2 years ago
5 0

Answer:

Question

Match each expression with the equivalent expanded expression.

0.5 (2x + 3)

- 10x - 3

1/3 ( 9 +81)

8x - 4

-5 (2x + 3/5)

-2x + 3

2 (4x-2)

x + 1.5

-3 (2/3x - 1)

30

Answer:



Step-by-step explanation:



Step-by-step explanation:

Question

Match each expression with the equivalent expanded expression.

0.5 (2x + 3)

- 10x - 3

1/3 ( 9 +81)

8x - 4

-5 (2x + 3/5)

-2x + 3

2 (4x-2)

x + 1.5

-3 (2/3x - 1)

30

Answer:



Step-by-step explanation:



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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
2 years ago
Let f(x)=x^4-3x^3+5x-3, f(-2)
BabaBlast [244]
f(-2)=(-2)^4-3(-2)^3+5(-2)-3
\\f(-2)= 16+24-10-3\\
f(-2)=30-10-3\\
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8 0
2 years ago
I dunno this answer... pwease help... if you're smart
zmey [24]

Answer:

H: (2, 14)

O: (4,15)

U: (6,14)

S: (2,10)

E: (6,10)

Step-by-step explanation:

the image on the grid is after doin x- 1 and y-7

to get the preimage do the inverse , x + 1 , y + 7

note- a coordinate is written as (x,y)

so, add 1 to all the x's and 7 to all the y's on the coordinates on the grid!

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3 0
3 years ago
3 4/6 mini-pizzas were left in the fridge; the children ate 1 2/3 of them. How much pizza is left for the adults? Give your answ
Naya [18.7K]

Answer:

It would be 2 whole pizza left for the adults. the improper fraction would be 2 1/2 or 5/2

Step-by-step explanation:

8 0
2 years ago
I don’t understand how to do 8. , 9. , and 10.
kenny6666 [7]

Answer:

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