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3 years ago

In trapezold ABCD, point D has coordinates D(1,3). If the trapezoid is translated

Mathematics

1 answer:

Arisa [49]3 years ago

8 0

Answer:

D’(-1,-2)

Step-by-step explanation:

Left = x -2 = 1-2 = -1

down = y-5 = 3-5 = -2

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The angles in a triangle are 100, 40, and 40 degrees. Classify the triangle by its angles and sides.

lara [203]

Answer:

F. Obtuse isosceles

Step-by-step explanation:

Since we have an angle that is 100 degrees, we have an obtuse angle

We have two angles that are 40, which means we have two sides that are equal length, because two angles have the same measure. That means it is isosceles

The triangle is an obtuse isosceles

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3 years ago

The diagonals of a rhombus are perpendicular.

Ivahew [28]

The rhombus always has perpendicular diagonals.

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3 years ago

Name a line that contains point P

Sveta_85 [38]

The only line that contains point P is 'n'.

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3 years ago

Mary Jackson gets a student rate of $27.50 a month for health insurance. There is a $200 deductible. She recently received treat

Digiron [165]

Answer:

the company's payment was $1720

Step-by-step explanation:

Mary's total cost (without the monthly premium) is $630

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3 years ago

Read 2 more answers

Two decimals numbers, to the thousandths, that have a sum of about 5 and a difference of about 3. Then do the math to prove it w

mina [271]

Answer:

The numbers are approximately: 4.000 and 1.000

Step-by-step explanation:

The given parameters can be expressed as:

$\frac{x}{1000} + \frac{y}{1000} \approx 5$

$\frac{x}{1000} - \frac{y}{1000} \approx 3$

Required

Determine the numbers

In each of the equations, multiply by 1000

$1000 * [\frac{x}{1000} + \frac{y}{1000} \approx 5]$

$x + y \approx 5000$

$1000 * [\frac{x}{1000} - \frac{y}{1000} \approx 3]$

$x-y \approx 3000$

So, we have:

$x + y \approx 5000$

$x-y \approx 3000$

Add the two equations

$x + x + y - y \approx 5000 + 3000$

$2x \approx 8000$

Solve for x

$x \approx 8000/2$

$x \approx 4000$

Substitute $x \approx 4000$ in $x + y \approx 5000$

$4000 + y \approx 5000$

$y \approx 5000 - 4000$

$y \approx 1000$

Using:

$\frac{x}{1000} + \frac{y}{1000} \approx 5$

We have:

$\frac{4000}{1000} + \frac{1000}{1000} \approx 5$

$4.000 + 1.000 \approx5$

<em>This implies that, the numbers approximates to 4.000 and 1.000, respectively.</em>

4 0

3 years ago