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lorasvet [3.4K]
3 years ago
15

Solve this problem???​

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

The denominator of the first term is a difference of squares, such that

4<em>a</em> ² - <em>b</em> ² = (2<em>a</em>)² - <em>b</em> ² = (2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)

So you can write the fractions as

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)/(2<em>a</em> + <em>b</em>)

Multiply through the second fraction by 2<em>a</em> - <em>b</em> to get a common denominator:

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)²/((2<em>a</em> + <em>b</em>) (2<em>a</em> - <em>b</em>))

((4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²) / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

Expand the numerator:

(4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²

(4<em>a</em> ² + <em>b</em> ²) - (4<em>a</em> ² - 4<em>ab</em> + <em>b</em> ²)

4<em>ab</em>

<em />

So the original expression reduces to

4<em>ab</em> / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

or

4<em>ab</em> / (4<em>a</em> ² - <em>b</em> ²)

upon condensing the denominator again.

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Further explanation:

First of all let us define prime factorization

Prime factorization consists of all the prime multiples of a number i.e. the factors should also be prime numbers

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70 = 7*10 => 10 is a composite number

70 = 2*5*7 => All factors are prime so

The prime factorization of 70 is 2*5*7

Keywords: Factorization, Prime factors

Learn more about prime factorization at:

  • brainly.com/question/12938965
  • brainly.com/question/13018049

#LearnwithBrainly

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