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lorasvet [3.4K]
3 years ago
15

Solve this problem???​

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

The denominator of the first term is a difference of squares, such that

4<em>a</em> ² - <em>b</em> ² = (2<em>a</em>)² - <em>b</em> ² = (2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)

So you can write the fractions as

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)/(2<em>a</em> + <em>b</em>)

Multiply through the second fraction by 2<em>a</em> - <em>b</em> to get a common denominator:

(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)²/((2<em>a</em> + <em>b</em>) (2<em>a</em> - <em>b</em>))

((4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²) / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

Expand the numerator:

(4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²

(4<em>a</em> ² + <em>b</em> ²) - (4<em>a</em> ² - 4<em>ab</em> + <em>b</em> ²)

4<em>ab</em>

<em />

So the original expression reduces to

4<em>ab</em> / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))

or

4<em>ab</em> / (4<em>a</em> ² - <em>b</em> ²)

upon condensing the denominator again.

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