Answer:
x = -4/11
Step-by-step explanation:
add the x values.
11x+8=4
subtract 8 from each sides
11x=-4
divide by 11
x=-4/11
Answer:
Step-by-step explanation:
When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.
Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.
Answer:
B. The ratio of the area of the scale drawing to the area of the painting is 1:16
C. The ratio of the perimeter of the scale drawing to the perimeter of the painting is 1:4
Step-by-step explanation:
The ratio of the area of similar figures/shapes = the square of the ratio of any of their side lengths
Since the scale drawing of the rectangular painting and the actual rectangular painting are similar, therefore,
The ratio of the area of the scale drawing to the painting = 1²:4²
= 1:16
Also, comparing the ratio of the perimeter of the scale drawing to the perimeter of the painting will be the same as the scale factor = 1:4
Answer: a because it’s using the commutative property of addition meaning it’s the same mathematical statement, it’s just moved around
Step-by-step explanation:
You’re absolutely amazing and I really appreciate that you’re trying to help others! And if you need anything yourself please feel free to ask :)