The complete question is
"Point P is the incenter of triangle ABC, PZ = 7 units, and PA = 12 units.
The radius of the incircle centered at point P is ? units."
The radius of the incircle centered at point P is 7 units.
We are given that point P is the incenter of the triangle, and is the center point of the incircle of the triangle.
<h3>What is incircle?</h3>
The incircle is defined as the largest circle that can be made in a triangle and is tangent to each side of the triangle.
Here, The radius of the circle is going to be a perpendicular line from point P to any side of the triangle.
In the triangle ,
PZ = PY = PX,
Each measure of value is equal to the radius of the circle.
Therefore, we already know that PZ = 7 units making the radius, r = 7 units.
Learn more about incircle;
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So for eliminating, you only solve for one variable first.
I solved for y, so I multiplied by -4 to eliminate the x.
Then I got y= -1
I then substituted that to one of the equations to get x.
You are looking for the circumference. which is C(circumference)=

x r (radius)
the radius is =to half of the diameter.
c=56.55
Answer:
32 and 27
Step-by-step explanation:
59 - 5 = 54
54 ÷ 2 = 27( smallest no. )
27 + 5 = 32( largest no. )
Answer:
the simplified answer is y= 63/8