Can some one solve 2 I’ll give a crown
2 answers:
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I saw the image that accompanied this problem.
4 identical isosceles trapezoid forming 2 parallelogram.
1 parallelogram has a base of 16 inches and its height is 10 inches.
We need to get the area of the parallelogram and multiply it by 2 before dividing it into 4 to get the area of each isosceles trapezoid.
Area of a parallelogram = base * height
A = 16 in x 10 in = 160 in²
160 in² x 2 parallelogram = 320 in²
320 in² / 4 tiles = 80 in²
The area of one tile is 80 square inches.
4 identical isosceles trapezoid forming 2 parallelogram.
1 parallelogram has a base of 16 inches and its height is 10 inches.
We need to get the area of the parallelogram and multiply it by 2 before dividing it into 4 to get the area of each isosceles trapezoid.
Area of a parallelogram = base * height
A = 16 in x 10 in = 160 in²
160 in² x 2 parallelogram = 320 in²
320 in² / 4 tiles = 80 in²
The area of one tile is 80 square inches.