The total number of 13-card hands that can be dealt is 52C13. Four of these are of the same suit. Therefore the required probability is given by:
The answer is 9×7=63 .25×9=2.25 +35=2.60 +35=2.95+35=3.30+35=3.65+35=4.00+4.00=8.00+55=8.55 that is the total 9 quarters and 7 nickels
The answer is 12 because u have to replace it -2(3)2(-1) and -2*3=-6 and 2(-1)=-2 and -6*-2=12