3 years ago

What must be added to 3x-7 to make x^2+4x-1

Mathematics

2 answers:

marta [7]3 years ago

3 0

3x-7+c=x^2+4x-1
find c
minus 3x from both sides
-7+c=x^2+x-1
add 7 to both sides
c=x^2+x+6

x^2+x+6 must be added

Gemiola [76]3 years ago

3 0

The term that can be added is the difference between the two expressions you have:

x^2+4x-1-(3x-7)

x^2+4x-1-3x+7

x^2+x+6

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