To add decimals, line up the decimal points.
Here are some examples.
1.2
1.43
10.2
2.5
938.290
21.001
After you line up the decimal points, just add and carry down the decimal point.
14.37
5.63
_____
20.00
So, the answer is 20.
Answer:
-3.4
Step-by-step explanation:
-11/2 +-2.1=-3.4
-2.1-3.4=-11/2
now, let's keep in mind that, the integers are consecutrive, therefore, if one is say 2, the other is either, 3 or 1, because 1,2,3 <--- notice, 1 is before 2 and 3 is after 2.
so say, our first integer is "a", then the next one can just be "a+1".
![\bf \begin{cases} a&=small\\ a+1&=\stackrel{consecutive}{large}\\ \end{cases}\qquad \begin{cases} \stackrel{\textit{4 times the small}}{4a}\\ \stackrel{\textit{13 greater than that}}{4a + 13} \end{cases}~\hfill \stackrel{\textit{large}}{a+1}=\stackrel{\stackrel{\textit{13 more than }}{\textit{4 times the small}}}{4a+13} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20a%26%3Dsmall%5C%5C%20a%2B1%26%3D%5Cstackrel%7Bconsecutive%7D%7Blarge%7D%5C%5C%20%5Cend%7Bcases%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7B%5Ctextit%7B4%20times%20the%20small%7D%7D%7B4a%7D%5C%5C%20%5Cstackrel%7B%5Ctextit%7B13%20greater%20than%20that%7D%7D%7B4a%20%2B%2013%7D%20%5Cend%7Bcases%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Blarge%7D%7D%7Ba%2B1%7D%3D%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7B13%20more%20than%20%7D%7D%7B%5Ctextit%7B4%20times%20the%20small%7D%7D%7D%7B4a%2B13%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

let's recall that, on the negative side in a number line, the closer to 0, the larger the number, therefore, -1,000,000 is a much <u>smaller</u> number than -1, because -1 is closer to 0, thus is larger.
A Ray y=4 . I think .If its wrong don't blame me
Answer:
5$??.
Step-by-step explanation:
If a magazine was 5$, 25-5= 20. So then, 20÷4= 5. There fore an eraser costs 5$.