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motikmotik
4 years ago
13

The solution set for a pair of equations is (3, -1). One of the equations is 2y = x - 5. Which of the following could be the oth

er equation?
Mathematics
1 answer:
timama [110]4 years ago
4 0
The points is small sorry
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Rotate RST 90° counterclockwise around the origin.<br>​
Nostrana [21]

The image of the triangle RST when rotated 90° counterclockwise around the origin is (-15,5), (-15,15) and (-5,10)

<h3>
How to rotate the triangle?</h3>

The coordinates of RST are given as:

R = (5,15)

S = (15,15)

T = (10,5)

The rule of 90° counterclockwise around the origin is:

(x,y) -> (-y,x)

So, we have:

R' = (-15,5)

S' = (-15,15)

T' = (-5,10)

Hence, the image of the triangle when rotated 90° counterclockwise around the origin is (-15,5), (-15,15) and (-5,10)

Read more about rotation at:

brainly.com/question/4289712

#SPJ1

4 0
3 years ago
1) Which expression is prime? A) 2x2 - 72 B) 3x2 - 147 C) 4x2 - x D) 6x2 + 7x + 3
Neporo4naja [7]

The answer is D)6x^2 + 7x + 3

7 0
3 years ago
Louis has 45 pencils and 75 pens to divide into gift bags at the fair. He does not want to mix the pens and pencils. He wants to
Rudiy27

15 pens and pencils

7 0
3 years ago
What is the equation of the line will mark you brainliest
Delvig [45]

so you're going to need to find the slope. in order to do that use (y2-y1)/(x2-x1)

(7-(-2))/(0-8)

simplify

9/-8

simplify -9/8

now using y=mx+b, we need to find b. so we can plug in the coordinates of (0,7) or (8,-2). let's use (8,-2) because it involves more math.

y=mx+b

-2=(-9/8)(8)+b

multiply (-9/8) by 8 to get -9

-2=-9+b

add 9 to both sides

7=b

so our equation is now

y=-(9/8)x+7

5 0
3 years ago
I have no idea how to do this. I can’t cooperate with the imaginary number, please help me
NeTakaya

Answer:

Step-by-step explanation:

This is a third degree polynomial because we are given three roots to multiply together to get it.  Even though we only see "2 + i" the conjugate rule tells us that 2 - i MUST also be a root.  Thus, the 3 roots are x = -4, x = 2 + i, x = 2 - i.

Setting those up as factors looks like this (keep in mind that the standard form for the imaginary unit in factor form is ALWAYS "x -"):

If x = -4, then the factor is (x + 4)

If x = 2 + i, then the factor is (x - (2 + i)) which simplifies to (x - 2 - i)

If x = 2 - i, then the factor is (x - (2 - i)) which simplifies to (x - 2 + i)

Now we can FOIL all three of those together, starting with the 2 imaginary factors first (it's just easier that way!):

(x - 2 - i)(x - 2 + i) = x^2-2x+ix-2x+4-2i-ix+2i-i^2

Combining like terms and canceling out the things that cancel out leaves us with:

x^2-4x+4-i^2

Remembr that i^2=-1, so we can rewrite that as

x^2-4x+4-(-1) and

x^2-4x+4+1=x^2-4x+5

That's the product of the 2 imaginary factors.  Now we need to FOIL in the real factor:

(x+4)(x^2-4x+5)

That product is

x^3-4x^2+5x+4x^2-16x+20

which simplifies down to

x^3-11x+20

And there you go!

4 0
4 years ago
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