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serious [3.7K]
3 years ago
5

Given g(x)=-x-1 find g(-4)

Mathematics
2 answers:
dmitriy555 [2]3 years ago
6 0

Answer:

g(-4) = 3

Step-by-step explanation:

g(x) = -x - 1

g(-4) = -(-4) - 1

g(-4) = 4 - 1

g(-4) = 3

coldgirl [10]3 years ago
4 0

Answer: 3

Step-by-step explanation:

g(-4)=-(-4)-1

g(-4)=4-1

g(-4)=3

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What is the algebraic expression of twelve minus the product of nine and a number
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Let's represent the unknown number with the variable x:
9x - 12
9x is the product of 9 and a number, and it is being subtracted by 12
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3 years ago
2 + x = 19 what is x
KonstantinChe [14]

Answer:

x = 17

Step-by-step explanation:

you just minus the 2

6 0
3 years ago
Y(z + y): use y = 2, and z = 4​
Pepsi [2]
2(4+2) so the answer is 12
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Find the sum of the polynomials. (3x3 + 4x2 - 2x + 1) + (x4 - x3 + 5x2 + 2x + 3) A. x4 + 2x3 + 9x2 - 4x + 4 B. x4 + 4x3 + 9x2 +
alisha [4.7K]
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7 0
4 years ago
Two parallel lines are intersected by a transversal. Prove: Angle bisectors of the same side interior angles are perpendicular.
coldgirl [10]

Answer:

The answer is given below

Step-by-step explanation:

From the diagram below,Let the line AB and CD be parallel line. Let transversal line EF cut AB at Y and transversal line EF cut CD at Z.

The bisector of ∠BYZ and ∠DZY meet at O. Therefore ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2

∠BYZ and ∠DZY are interior angles.

∠BYZ + ∠DZY = 180 (sum of consecutive interior angles)

∠BYZ/2 + ∠DZY/2 = 180/2

∠BYZ/2 + ∠DZY/2 = 90°

In ΔOYZ:

∠YZO + ∠ZYO + ∠YOZ = 180 (sum of angles on a straight line).

But  ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2

∠DZY/2 + ∠BYZ/2 + ∠YOZ = 180

90 + ∠YOZ = 180

∠YOZ = 180 - 90

∠YOZ = 90°

Therefore Angle bisectors of the same side interior angles are perpendicular.

7 0
3 years ago
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