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3 years ago

I need help is it A B C or D

Mathematics

1 answer:

iVinArrow [24]3 years ago

8 0

Pretty sure it's D as population is decreasing at a decreasing rate...

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MRS.Bonnette's recipe for banana bread calls for 3 and one fourths cups of sugar. She wants to make 6.5 batches so that she has

densk [106]

Answer:

$21/ \frac {1}{8}$

Step-by-step explanation:

Since we're given that a batch requires 3 and one fourths cups of sugar, this is written as

$3/ \frac {1}{4}$

If she wants 6.5 batches then we just cross multiply

1 batch= $3/ \frac {1}{4}$

6.5 batches=x

X= $6.5\times 3/ \frac {1}{4}$

X= $6/ \frac {1}{2}\times 3/ \frac {1}{4}$

X= $\frac {13}{2}\times \frac {13}{4}$

X= $\frac {169}{8}$

X= $21/ \frac {1}{8}$

6 0

3 years ago

PLEASE HELP!!! BRAINLIESt!! THANK YOUU

vredina [299]

Answer:

Step-by-step explanation:

7 0

3 years ago

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Sum of three Consecutive integers of 384

Burka [1]

The three consecutive integers are 127, 128, 129

8 0

3 years ago

Use the Rational Zeros Theorem to write a list of all potential rational zeros. f(x) = x3 - 5x2 + 8x - 24

masha68 [24]

If I remember correctly this would be obtained from the factors of -24

so i think its +/-1, +/-2, +/- 3, +/- 4, +/- 8, +/- 6 , +/-12, +/-24

Sorry but i cant be sure

6 0

4 years ago

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Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago