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3 years ago

Pleaseee i need help will mark brainliest

Mathematics

1 answer:

Kipish [7]3 years ago

4 0

Answer:

Is that canvas? .-.

⬇ Anyways, hey bud! The answer is down below ⬇

The answers are bolded so watch out for those!

Part 1

a. Complete this table showing some possible combinations of the number of each type of game being played;

Chess games (x) | Poker games (y)

1) 28 divided by 2 = 14 1) 8x4 = 32 people

2) 12x2=24 people 2) 36 divided by 4 = 9

3) 0 3) 15x4 = 60 people

4) 2x2=4 people 4) 56 divided by 4 = 14

Part 2 (Just a little extra ;] I love math :D)

b. There are 3 more games of poker being played than games of chess being played;

Y = x+3

60 = 2x+4y

Y = 8+3

Y = 11

60 = 2x+4(x+3)

60 = 2x+4x+12

$\frac{48}{6} = \frac{6x}{6}$

8 = x

8 games of chess are played and 11 games of poker.

Step-by-step explanation:

None, but on Part 1 you were actually correct! Good job!

You may have a great day! Bye! :D

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Pls answer quickly. Thanks!

Gwar [14]

Answer:

the answer is D

Step-by-step explanation:

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3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

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3 years ago

Dion has a pizza with a diameter of 10 1/3 in . Is the square box shown big enough to fit the pizza inside? The box is 10.38 in

Artemon [7]

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3 years ago

These scatterplots represent the monthly sales and advertising costs of a company. Which trend line is the best fit for the data

Lunna [17]

Answer:

Option D

Step-by-step explanation

I did the assignment

8 0

3 years ago

Read 2 more answers

Does anyone know how to do this, i’ll give you brainliest and there’s 16 points

leva [86]

6y-4=4y+2

2y=6, so y=3.

Plugging it in, you get that AC equals 4*3+2=14.

This is an isosceles triangle.

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3 years ago