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anygoal [31]
3 years ago
11

LITERALLY THE MOST HARDEST QUESTION TO EVER EXIST ON THIS PLANET AND QUITE POSSIBLY THIS DIMENSION IF DIMENSION QARPING WAS EVEN

POSSIBLE LIKE IN RICK AND MORTY!
if f(x)=1/2 x-2 what is the value of f(4)
Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
Plug in 4 for the value of x.

f(4)= 1/2(4)-2
f(4)= 2-2
f(4)= 0

Final answer: 0
EastWind [94]3 years ago
6 0

Answer:

all you got 2 do is plug in 4 for the value of x.

Step-by-step explanation:

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375 students do not like red

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Solve for t.<br> -t = 9(t-10)<br> pls help
Vinvika [58]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
What does unit rate mean​
satela [25.4K]

Answer:

Unit rate describes how many units of the first type of quantity corresponds to one unit of the second type of quantity. Some common unit rates are miles, per hour, cost per item, earnings and per week

Step-by-step explanation:

6 0
3 years ago
Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0
2 years ago
Find the nth terms of the following Ap 100, 91, 82​
Rom4ik [11]

Answer:

The nth term is 109-9n

Step-by-step explanation:

Here, we want to find the nth term of the given arithmetic sequence

Mathematically, we have the nth term as;

Tn = a + (n-1)d

where a is the first term which is 100 in this case

d is the common difference which is the value obtained by subtracting the preceding term from the succeeding term; it is constant throughout the sequence

The value here is thus;

82-91 = 91-100 = -9

Substituting these values

Tn = 100 + (n-1)-9

Tn = 100 -9n + 9

Tn = 100 + 9 - 9n

Tn = 109-9n

6 0
3 years ago
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