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1 answer:
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Answer:
- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)
Explanation:
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In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:
It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:
It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.
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Answer:
See explanation and image attached
Explanation:
The reaction of (R)-2-chloro-3-methylbutane with potassium tert-butoxide yields a monosubstituted alkene .
Since the base is bulky, the Hoffman product predominates because attack occurs at the less hindered carbon atom to yield the major product as shown.
The alkene reacts with HBr at the secondary carbon atom to yield a carbocation intermediate which is flat and planar. Attack on either face of the carbocation yields a racemic mixture of the (2R) and (2S) products.
Rearrangement of the carbocation to yield a tertiary carbocation gives the 2-bromo-2-methyl butane product as shown in the image attached.
