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Lelu [443]
3 years ago
6

Variation definition

Chemistry
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

Explanation:

Variation problems involve fairly simple relationships or formulas, involving one variable being equal to one term. Here follows the most common kinds of variation.

The constant of variation in a direct variation is the constant (unchanged) ratio of two variable quantities. In the following equation y varies directly with x, and k is called the constant of variation:

y=kx

Another form of variation is the inverse variation which works when there is a relationship between two variables in which the product is a constant. When one variable increases the other decreases in proportion so that the product is unchanged.

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Answer:

second rock...I know it

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Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.
qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m= 32 g
  • ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 \frac{J}{g*C} *14 °C

Solving:

Q= 1,874.432 J

<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>

7 0
3 years ago
How do weathering and deposition differ?
Paul [167]
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1 year ago
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A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressu
dangina [55]

Answer:

Partial pressure of Ne is 0.61 atm.

Explanation:

Mole fraction of a gas (x) in mixture = (no. of moles of the gas in mixture)/(total no. of moles of gases in mixture)

Here, total no. of moles of gases = (0.32 + 0.56) moles = 0.88 moles

So, mole fraction of Ne in mixture, x_{Ne}=\frac{0.56}{0.88}=0.64

Let's assume both He and Ne along with their mixture behaves ideally,

Hence, in accordance with Dalton's law of partial pressure-

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Where, P_{Ne} and P_{total} are partial pressure of Ne and total pressure respectively.

So,  P_{Ne}=(0.64)\times (0.95atm)=0.61atm

So, partial pressure of Ne is 0.61 atm.

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3 years ago
TRUE/FALSE: A solution is a mixture containing particles that settle out of the mixture if left undisturbed.
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The answer is False.

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