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andrew-mc [135]
2 years ago
15

Carlos started baking at 6:43 PM and finished at 7:32

Mathematics
2 answers:
ser-zykov [4K]2 years ago
7 0

Answer:

It took him 49 minutes

Artist 52 [7]2 years ago
3 0

Answer:

It took him 49 minutes

Step-by-step explanation:

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If the square root of p2 is an integer greater than 1, which of the following must be true? I. p2 has an odd number of positive
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Answer:

Option | and Option || is True

Step-by-step explanation:

Given:

If the square root of p^{2} is an integer greater than 1,

Lets p = 2, 3, 4, 5, 6, 7..........

Solution:

Now we check all option for p^{2}

Option |.

p^{2} has an odd number of positive factors.

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Number of factor is 3

Let p=3

The positive factor of 3^{2}=9=1,3,9

Number of factor is 3

So, p^{2} has an odd number of positive factors.

Therefore, 1st option is true.

Option ||.

p^{2} can be expressed as the product of an even number of positive prime factors

Let p=2

The positive factor of 2^{2}=4=1,2,4

4=2\times 2

Let p=3

The positive factor of 3^{2}=9=1,3,9

9=3\times 3

So, it is expressed as the product of an even number of positive prime factors,

Therefore, 2nd option is true.

Option |||.

p has an even number of positive factors

Let p=2

Positive factor of 2=1,2

Number of factor is 2.

Let p=4

Positive factor of 4=1,2,4

Number of factor is 3 that is odd

So, p has also odd number of positive factor.

Therefore, it is false.

Therefore, Option | and Option || is True.

Option ||| is false.

4 0
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Step-by-step explanation:

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