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Step2247 [10]
3 years ago
14

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:

Step-by-step explanation:

y=x+69

zaharov [31]3 years ago
4 0

Answer:

y=x+69

Step-by-step explanation:

5+69=74

6+69+75

etc.

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What is f(7) for function f(x)=2x - 5
Kobotan [32]

Because in the function f(x) all you do is plug in the value that is given...7

2*7-5=14-5=9

Your answer is 9.

8 0
4 years ago
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A scale model of a merry-go-round and the actual merry-go-round are similar. a. How many times greater is the base area of the a
Kipish [7]
The area ratio is the square of the linear dimension ratio. So if the merry-go-round base is circular, the area contains the square of the radius. If a polygon, the base can be divided into triangles. The area of each triangle involves the product of the base length and the height, so since both have the same change of length, the product will square the scaling ratio.
Let’s say the ratio of corresponding lengths is x:1 then the ratio of the base areas is x²:1.
The question doesn’t provide any figures.
Let’s put some in as an example. Let the actual merry-go-round be circular with a diameter of 20 feet, while the model is one foot in diameter. So the ratio of the actual ride and it’s model is 20:1. The area of the base of the actual ride is 100π sq ft. The area of the base of the model is π/4 sq ft. We expect the ratio of these areas to be 20²=400. 100π/(π/4)=400.
6 0
3 years ago
II
Anon25 [30]

Answer:

2.17

Answer and Explanation:

The critical value of z for 97% confidence interval is 2.17, which is obtained by using a z score table, that is: {eq}P(-2.17 < Z <...

5 0
3 years ago
Which expression is equivalent to -9x^-1y^-9/-15x^5/y^3? Assume x=0,y=0
Juliette [100K]

Answer:

B

Step-by-step explanation:


8 0
3 years ago
The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).
Effectus [21]

Answer:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

Step-by-step explanation:

Given the quadratic equation as:

2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0

Let us put sinx=y for simplicity of the equation:

Now, the equation becomes:

2y^2+y-1=0

Now, let us try to solve the quadratic equation:

\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1

So, the solution to the given trigonometric quadratic equation is:

sinx = \dfrac{1}{2}

and

sinx=-1

Let us try to find the values of x in the interval [0, 2\pi).

sin\theta can have a value equal to \frac{1}{2} in 1st and 2nd quadrant.

So, x can be

30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}

For sinx=-1,

x = 270^\circ\ or\ \dfrac{3 \pi}{2}

So, the answer is:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

7 0
3 years ago
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