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PilotLPTM [1.2K]
2 years ago
11

Given m||n, find the value of x. + >m (5x+19) (6x+1)°

Mathematics
2 answers:
Radda [10]2 years ago
8 0
5x+19=6x+1 because of parallel postulate.
x=18
vovikov84 [41]2 years ago
7 0
X=18 beuhhhdhshsjsj what he said
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Dr. Jane is studying the growing population of a species of jellyfish in a body of water. Each year, she records the population
olya-2409 [2.1K]

Answer:

983040

Step-by-step explanation:

Second Year : 15x4=60

Third Year : 60x4=240

Fourth Year : 240x4=960

Fifth Year : 960x4=3840

Sixth Year : 3840x4=15360

Seventh Year : 15360x4 = 61440

Eighth Year: 61440x4=245760

Ninth Year : 245760x4= 983040

4 0
3 years ago
Read 2 more answers
Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
3 years ago
Read 2 more answers
What is the measure of DAE?<br> 45°<br> 46°<br> 91°<br> 146°
Schach [20]

Since BAF is opposite of DAE, they are equal to each other.

134 - 89 = 45

The correct answer is 45

6 0
3 years ago
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The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
Ms. Carol sold 346 child tickets<br> and 253 adult tickets. How<br> many tickets did Ms. Carol sell?
pickupchik [31]
She sold 346+253=599 tickets.
8 0
3 years ago
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