Answer:
100 Candy Bars
Step-by-step explanation:
Hey!
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Ayden wants to sell a total of $150 worth of candy bars for his school fundraiser. Each candy bar costs $1.50. How many candy bars will he have to sell in order to meet his goal?
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We can create an algebraic Equation to solve this.
<u>- We know that Each Candy Bar costs $1.50.</u>
<u>-We multiply the Amount of Candy Bars with the price. </u>
<u>-We know the profit should be $150</u>
⇒ 1.50x = 150
-<u>Divide</u> by 1.50 on both sides
⇒ 1.50x/1.50 = 150/1.50
-<u>Simplify</u>
⇒ x = 100
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<em>Hope I Helped, Feel free to ask any questions to clarify :)
</em>
<em>
Have a great day!
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<em>
More Love, More Peace, Less Hate.
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<em> -Aadi x</em>
Composite number is made up of 2 or more prime numbers
a prime number is only made up of itself and 1
composite and prime numbers are like oposites
a prime is not a composite but it is a prime number
confusing quesiton
First represent your 3 consecutive integers as follows.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.
Simplifying on the left side we get 3x + 3 = 84.
Now subtract 3 from both sides to get 3x = 81.
Dividing both sides by 3, we find that <em>x = 27</em>.
Finally, make sure you list all your answers.
If <em>x </em>is 27 then <em>x </em>+ 1 is 28 and <em>x </em>+ 2 is 29.
Answer:
.
Step-by-step explanation:
How many unique combinations are possible in total?
This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination
.
How many out of that 2,118,760 combinations will satisfy the request?
Number of ways to choose 2 red candies out a batch of 28:
.
Number of ways to choose 3 green candies out of a batch of 8:
.
However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing
.
The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:
.
A(n) = –3 • 2⁽ⁿ⁻¹⁾
for n = 1 , A₁ = -3.(2)⁰ = -3
for n = 2 , A₂ = -3.(2)¹ = -6
for n = 3 , A₃ = -3.(2)² = -12
for n = 4 , A₄ = -3.(2)³ = -24
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for n = 8 , A₈ = -3.(2)⁷ = -384
