Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Answer:
the artist cuts off 10 inches of ribbon in total
Step-by-step explanation:
2.5 × 4 = 10
Answer: (2, -3)
Step-by-step explanation: (2, -3) is the new ordered pair rotated 270°
Answer:
shown below
explanation:
<em>first</em><em> </em><em>off</em><em>,</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em> </em><em>and</em><em> </em><em>1</em><em>3</em><em>4</em>
12x=134+10
12x=144
<em>then</em><em> </em><em>you</em><em> </em><em>simplify</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>look</em><em> </em><em>like</em><em> </em><em>this</em><em>:</em>
12x. 144
___ = ___
12. 12
144÷12=12
so the answer is option c.12
<h2>
hope it helps!!</h2>
There are a total of 7C2 of options for Ryan's mom to choose.
If Ryan's mom picks Saturday and Sunday, this is the only 1 option in those 7C2 of options. Thus, the propability is (1 / 7C2) × 100% = 4.762%.
