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3 years ago

Hey plese helppppp . Question: Evaluate: b²- 4ac. if a=5, b=-2,c=-3

Mathematics

2 answers:

sergey [27]3 years ago

4 0

Answer:

Step-by-step explanation:

b²- 4ac

Let a=5, b=-2,c=-3

(-2)^2 - 4(5) (-3)

4 +60

Aliun [14]3 years ago

3 0

Answer:

Step-by-step explanation:

(-2)^2 - 4(5)(-3)

4 - - 60

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What is the answer to this question?<br> 6x - 6 < 12

rosijanka [135]

Answer:

X<3

Step-by-step explanation:

6x−6+6<12+6

6x<18

Step 2: Divide both sides by 6.

6 divded by 6 = 1

18 divided by 6= 3

therefore the answer would be

X<3

7 0

3 years ago

Read 2 more answers

A function of random variables used to estimate a parameter of a distribution is a/an _____.

stiks02 [169]

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

<h3>What are the parameters of a random variable?</h3>

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

An unbiased estimator exists in which the difference between the estimator and the population parameter grows smaller as the sample size grows larger. This simply indicates that an unbiased estimator catches the true population value of the parameter on average, this exists because the mean of its sampling distribution exists the truth.

Also, we comprehend that the bias of an estimator (b) that estimates a parameter (p) exists given by; E(b) - p

Therefore, an unbiased estimator exists as an estimator that contains an expected value that exists equivalent to the parameter i.e the value of its bias exists equivalent to zero.

Generally, in statistical analysis, the sample mean exists as an unbiased estimator of the population mean while the sample variance exists as an unbiased estimator of the population variance.

Therefore, the correct answer is an unbiased estimator.

To learn more about unbiased estimators refer to:

brainly.com/question/22777338

#SPJ4

4 0

1 year ago

2) Kari is flying her kite at the park. She has let

Ket [755]

Answer:

approx 58 yard we can determine it by pithagoras theorem

6 0

3 years ago

Solve the equation for t^2 +15t=-36.

Mice21 [21]

Answer:

t=−3 or t=−12

Step-by-step explanation:

Step 1: Subtract -36 from both sides.

t2+15t−(−36)=−36−(−36)

t2+15t+36=0

Step 2: Factor left side of equation.

(t+3)(t+12)=0

Step 3: Set factors equal to 0.

t+3=0 or t+12=0

t=−3 or t=−12

7 0

3 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$