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dlinn [17]
3 years ago
5

The number of students in an school building that have the flu after t days is given by the function

Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0

Step-by-step explanation:

p(0) =  \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} }  =  \frac{800}{1 + 49}  =  \frac{800}{50}  = 16

200 =  \frac{800}{1 + 49 {e}^{ - 0.2t} }  \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t}  = 800 \\ 9800 {e}^{ - 0.2t}  = 600 \\  {e}^{ - 0.2t}  =  \frac{3}{49}  \\  ln( {e}^{ - 0.2t} )  =  ln( \frac{3}{49} )  \\ -  0.2t =  - 2.793 \\ t = 13.96 = 14

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In a right triangle, one of the exterior angles measures 155°. What is the measure of the non-adjacent, non-right angle?
tangare [24]
180 - 155 = 25
90 - 25 = 65
<span>B: 65 </span>°
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Roulette is a casino game that involves spinning a ball on a wheel that is marked with numbered squares that are red, black, or
a_sh-v [17]

Answer:

.6315 or 63.15%

Step-by-step explanation:

not sure if the question is trying to be tricky, but there are 0 and 00 which makes a total of 38  numbers on the wheel (and they are less than 12)

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6 0
2 years ago
Eight packages of strawberries cost $24. How many packages can you buy for $12
romanna [79]
4 packages, because 24/12=2, 8/2=4 packages.
8 0
3 years ago
Please show your work. Thank you for taking the time of day to help me!
34kurt

Answer:

30

Step-by-step explanation:

Look at the bottom line of the chart.

He sold 41 sides of French fries and 40 sides of onion rings.

41 + 40 = 81

Since he sold a total of 81 sides with bacon cheeseburgers, that means he sold a total of 81 bacon cheeseburgers.

We have a ratio:

81 bacon cheeseburgers to 40 sides of onion rings

Now he sold 120 bacon cheeseburgers, so we set up a proportion to find the number of sides of onion rings. Let the unknown number be x.

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7 0
3 years ago
Read 2 more answers
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
Read 2 more answers
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