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dlinn [17]
3 years ago
5

The number of students in an school building that have the flu after t days is given by the function

Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0

Step-by-step explanation:

p(0) =  \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} }  =  \frac{800}{1 + 49}  =  \frac{800}{50}  = 16

200 =  \frac{800}{1 + 49 {e}^{ - 0.2t} }  \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t}  = 800 \\ 9800 {e}^{ - 0.2t}  = 600 \\  {e}^{ - 0.2t}  =  \frac{3}{49}  \\  ln( {e}^{ - 0.2t} )  =  ln( \frac{3}{49} )  \\ -  0.2t =  - 2.793 \\ t = 13.96 = 14

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Two boxes have the same volume. One box has a base that is 2 inches by 2 inches. The other box has a base that is 4 inches by 4
lianna [129]

Answer:

4 times as tall.

Step-by-step explanation:

Volume of the box with the smaller base = 2*2* h1 = 4h1 where h1 is its height.

Similarly the volume of the larger base box =  4*4 * h2 = 16h2 with height h2.

So the ratio of their volumes is  16h2 / 4h1 = 4h2 / h1.

Now the volumes are equal so 4h2 = h1.

Therefore   h2 = h1/4  so h1 = 4h2.

The box with the smaller base is 4 times as tall as the other box.

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3 years ago
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1. Eric has $115 to spend on back to school clothes. So far, he has spent $90. Write an inequality to show how much more money E
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3 years ago
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crimeas [40]

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Step-by-step explanation:

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2 years ago
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Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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