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Temka [501]
3 years ago
13

Find the area of the figure.

Mathematics
1 answer:
Kruka [31]3 years ago
8 0
Divide the shape into a rectangle and a triangle.

A(rectangle) = bh
A = 8*3
A = 24

A (triangle) = (bh)/2
A = (3*3)/2
A = 4.5

24 + 4.5 = 28.5
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Round to the nearst hundredh 58.635
Aleonysh [2.5K]
58.635 rounded to the nearest hundreth is:

58.6 because 3 is less than 5

Hope I Helped You!!!
5 0
2 years ago
What are the solutions of the quadratic equation (x + 3)2 = 49
Korvikt [17]

the right answer is

x = 4 and x = –10

I just take the test and I got it right I hope yall get it right to


8 0
3 years ago
Read 2 more answers
Question 5 of 10
musickatia [10]

Answer:

25 in ^2

Step-by-step explanation:

First find the area of the circle

A = pi r^2

A = 3.14 ( 4.3)^2

A =58.0586

The take the fraction of the circle that is shaded

A circle is 360 degrees

155/360

155 /360 * the  total area = area shaded

31/72 * 58.0586 = 24.99745278 in ^2

Rounding yields 25 in ^2

4 0
3 years ago
Read 2 more answers
Cliff Branch bought a home with a 10.5% adjustable rate mortgage for 30 years. He paid $9.99 monthly per thousand on his origina
vichka [17]
I'm Unsure, But Here's What I Found.

9.99×65=649.35

10.68×65=694.2

((10.68÷9.99)−1)×100=6.9%
4 0
3 years ago
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The probability all of the students in this class will be present and on time is 3/10. The probability all of the students are p
cestrela7 [59]

Answer:

3/4

Step-by-step explanation:

A: students present
B: students on time

P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5

P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present

So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5

7 0
2 years ago
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