All categories

3 years ago

Simplify the expression (6x^3 divided by 3x^4)^2

Mathematics

2 answers:

DIA [1.3K]3 years ago

5 0

(6x^3/ 3x^4)^2
= (2/x)^2
= 4/x^2

hope it helps

Evgesh-ka [11]3 years ago

3 0

(6x^3/3x^4)^2 = (2/x)^2 = 4/x^2

You might be interested in

ILL BRAINLIEST YOU PLEASE HELP ME

Degger [83]

Answer:

63 cause there equal

Step-by-step explanation:

5 0

3 years ago

OMG PLEASE Help me !!!! ILL GIVE YOU BRAINLIEST !!! Explain in order to get it

Doss [256]

Answer:

I'm not sure but I believe the correct answer is line L2.

Step-by-step explanation:

It seems to be closer to more points than the other lines.

If it is not L2, it must be L3.

4 0

3 years ago

What the rate of change for f(t)=70(5/2)^t help

denis23 [38]

5/2
70 is the constant number that doesn’t change, but anytime you increase t you are raising it above 5/2. So every time you grow 5/2.

3 0

2 years ago

When a number is divided by -3, the result is 12 more than the number what is the number?

olga55 [171]

X/-3 = 12 + x
x = -36 - 3x
4x = 36
x= = 9

The number is 9.

8 0

3 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3>Correct Question :-</h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3>Given :- </h3>

We have AP, 

$\sf{ 2 , 14 ,.... 98 }$
AP is the arithmetic progression or a sequence of numbers in which succeeding number is differ from preceeding number by a common value.

<h3>Solution :-</h3>

We have an AP :- 2 , 14 .....98

Therefore,

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

Here,

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

Now, 

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago