Answer:
The measure of one interior angle of a regular pentagon is 108 degrees.
Step-by-step explanation:
Use a digital ruler.
The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of
- height, h = apothem of the hexagon = 2 cm and
- base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>
So, the area of this triangle is A = 1/2bh
= 1/2 × 1. 5 cm × 2 cm
= 1.5 cm × 1 cm
= 1.5 cm²
<h3>Area of the hexagon</h3>
Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A
= 6 × 1.5 cm²
= 9.0 cm²
So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Learn more about area of a hexagon here:
brainly.com/question/369332
Answer:
2x > 10+4
x > 14/2
x > 7
Step-by-step explanation:
Answer:
Step-by-step explanation:
An ellipse with vertices (-8, 0) and (8, 0)
Distance between two vertices = 2a
Distance between (-8,0) and (8,0) = 16
2a= 16
so a= 8
Vertex is (h+a,k)
we know a=8, so vertex is (h+8,k)
Now compare (h+8,k) with vertex (8,0) and find out h and k
h+8 =8, h=0
k =0
a minor axis of length 10.
Length of minor axis = 2b
2b = 10
so b = 5
General formula for the equation of horizontal ellipse is
a= 8 , b=5 , h=0,k=0. equation becomes
Your answer for this is 86.49
